Search results

I think i might be able to get something around 12-13 now. But i still remember the good old days of year 8 when i did a 5 something, which caused me to puff and be sore for a whole week. I miss the weekly KFCs...

Never read it and never well. All i know from the trailers that ive seen is that, the vampire dude's girl is hot. Shes also in adventure land as well. Forgot her name tho, its a shame.

Na, I done it ur way. Got the same answer. Thanks for the help.

I think its actually, p<-1/root3. Timothy forgot to change signs when doing division. p^2>1/3 p= 1/root3 or -1/root3 Solve via graph. p>1/rt3 or p<-1/rt3 since it is negative def, p<0 thus p<-1/rt3.

Wait a second. Isnt mine intergration also right?

UFC is actually alright, cause its real. (Unless some1 wants to correct me). But WWE is completely fake. Its horrid and just isnt entertaining at all. Perhaps its due to my violent and cruel nature, that would only be fufilled by real, action. Not this corny and awkard WWE crap.

zzz... but how did u get 2/3pi. Because that was the right anwer. Im just curious and want to know.

What... you didnt integrate it. How did you solve it then? What i meant was that the tangent cut the y-axis below at y = -2. Thus the area between the parabola and the tangent and x-axis, is above the x-axis. Otherwords my workings... \pi (\int_{0}^{1}(2x^2)^2dx - \int_{1}^{1/2}...

Timothy, but dosent it say the intesection with the x-axis? Meaning anything belwo the x-axis is discounted. If you can pleaes post solution.

re: The Official F1 Thread Webber is going to his old form again. Being 5-10th like last year. I adore the guy, but its true, he needs to Step Up and dance with the podium. EDIT: that was a really shit pun.

Is your friend female? Cause its something a girl would say. She obviously needs more commitment. Stop playing around and give her the dam ring already.

re: The Official F1 Thread I recon his car wouldnt of being competitive enough for that race. Ferrari and force india were way too strong.

Im gona go. But I think it might to way early for me.

Any1 else for the above?

What speed for running are we talking about here? Speedwise, i think jogging is only a bit slower then running. TO OP: I would probably last about 1hour max mabey. It woudl depend on my state of mind but also physical condition.

Also if some1 can help me in this question that would be great. Find the equation of the tangent to the parabola y=2x^2 at (1,2). Calculate its point of intersection with the x-axis and the volume of the solid formed when the area between the parabola, the tangent line and the xaxis is...

Awesome. Thanks os much to the above.

What about 2? Anyone? Its from Fitz.

Being ready since 1992. Seriously though, I am a bit worried. But still excited.

I have two questions. 1. Find the equation of the curve COD assuming it is of the form y=ax^2n. C(-60,18) O(0,0), D(40,8). 2.Line AB: 20y=x+480 Curve CD: y=x^2/200 A(-60,21) B(40,26) Find the area between the line AB and the Curve CD, between x= 40, x=-60 I got 1883 1/3 but the answer...