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AAAA PPP OO NN R G Z Well this is a good way to start, by first grouping the letters by the frequency and then determining the cases It'll involve a lot of cases I'm guessing I shall try this later tonight

Edit: Okay, my solution to the volumes question is wrong as I interpreted the question incorrectly This solution would fit the question "Find the volume of the solid formed by rotating the ellipse x^2/16 + y^2/4 = 1 around the y axis using the method of slicing" End edit I think that's right...

The more efficient way is to declare that it's an odd integral and say it's 0, instead of actually integrating it Let f(x) = tan x . ln (x^2 + e) f(-x) = tan -x . ln ([-x]^2 + e) = - tan x . ln (x^2 + e) = -f(x) Therefore f(x) is an odd function Therefore, the integral = 0 Haha guys, remember...

conics2008 should be able to do this without a problem yea?

The equation x^3 + qx + r = 0 has roots A, B and C. Find the expression for A^5 + B^5 + C^5

Okay, let's do this one step at a time We look at this: x = pi - pi/3, pi + pi/3, 3pi - pi/3, 3pi + pi/3, 5pi - pi/3, 5pi + pi/3 ... And we notice the alternating plus and minus signs Therefore we can simplify this to x = pi ± pi/3, 3pi ± pi/3, 5pi ± pi/3 ... Now look at the coefficients of...

I'm guessing it's a mathematical induction question since we have to show for n >= 2 When n = 2, u(2) = (2 + 27) / 3 = 29 / 3 > 3 Therefore it is true for n = 2 Assume it is true for n = k ie. u(k) = (2[u(k-1)]^3 + 27) / 3([u(k-1)]^2 > 3 Consider n = k + 1 u(k + 1) = (2[u(k)]^3 + 27) /...

It's so relevant :|

I suggest that you work more on these types of questions as these are the fundamental identies of trigonometry, and are essential in harder questions And lmfao "aMUSEd1977 Sucks The Cock"

Don't you just feel like doing maths for fun, but when you go onto BOS there aren't any questions? Well you can here now. Maths is fun after all =) Rules: 1. Attempt the question from the newest poster. If you can do it, post the solution up (this includes working out). Remember to leave...

cis @ is the notation for cos @ + isin @ It saves time and space writing it I guess xD

cos 2x = 2cos^2 x - 1 Let x = u/2 cos u = 2cos^2 u/2 - 1

Hahaha "fake", I laughed when I read it in your working out Sif make up your own terms =p Ahh I write my solutions in Photoshop with a graphics tablet, then I use Paint Shop Pro to crop and decrease the colour depth And yea, that's the double/half angle formula

Eh haven't you finished your HSC VirgCap86?

Similarly, equate the imaginary parts

Ha...

Right now our main focus is the HSC, correct? We need to first build up our fluency on what's required in the syllabus THEN we can go beyond

conics2008 also asked for sin^m x.cos^m x, which should bring out the same results as sin^n x.cos^n x. The only difference is the parameter: in this case n instead of m; and this doesn't affect the results For recurrence formulae with both m and n requires two parameters, and this is out of the...

For some reason I doubt myself. Check my working for any mistakes.

Wait, what exactly are you asking?