MedVision ad

4U Revising Game (1 Viewer)

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,255
Gender
Male
HSC
N/A
Mr harism

Thank u. In my hurry, I dropped the x^n. I've amended my solution.
 
Last edited:

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,390
Gender
Male
HSC
2006
Would've been much simpler if you just do:



Question:

Suppose f(x) = 1/x + sin²(πx) / πx². By considering the first derivative, prove that f(x) is decreasing for x > 0.
 
Last edited:

harism

New Member
Joined
May 9, 2008
Messages
25
Gender
Male
HSC
2009
yea i see drongoski.
its a nice solution.
(call me haris, lol)

btw, trebla.
my god.
gurmies was right about you.
your epic.

i would never have seen that solution coming. =O
good work!
 
Last edited:

azureus88

Member
Joined
Jul 9, 2007
Messages
278
Gender
Male
HSC
2009
[maths]f'(x)=-\frac{1}{x^2}+\frac{1}{n}\frac{2nx^2\sin(nx)\cos(nx)-2x\sin^2(nx)}{x^4}\\=-\frac{1}{x^2}+\frac{1}{n}\frac{nx\sin(2nx)-2\sin^2(nx)}{x^3}\\=\frac{-nx+nx\sin(2nx)+\cos(2nx)-1}{nx^3}\\=\frac{nx(\sin(2nx)-1)+(\cos(2nx)-1)}{nx^3}\\<0\,\,$for$\,\,x>0\\$since$\,\,-1\leq \sin(2nx)\leq 1\,\,$and$\,\,-1\leq \cos(2nx)\leq 1\\$and when$\,\,\sin(2nx)=1,\cos(2nx)\neq 1[/maths]
 
Last edited:

gurmies

Drover
Joined
Mar 20, 2008
Messages
1,209
Location
North Bondi
Gender
Male
HSC
2009
[maths]f'(x)=-\frac{1}{x^2}+\frac{1}{n}\frac{2nx^2\sin(nx)\cos(nx)-2x\sin^2(nx)}{x^4}\\=-\frac{1}{x^2}+\frac{1}{n}\frac{nx\sin(2nx)-2\sin^2(nx)}{x^3}\\=\frac{-nx+nx\sin(2nx)+\cos(2nx)-1}{nx^3}\\=\frac{nx(\sin(2nx)-1)+(\cos(2nx)-1)}{nx^3}\\<0\,\,$for$\,\,x>0\\$since$\,\,-1\leq \sin(2nx)\leq 1\,\,$and$\,\,-1\leq \cos(2nx)\leq 1\\$and when$\,\,\sin(2nx)=1,\cos(2nx)\neq 1[/maths]
I think it's pi, not n...?
 
Last edited:

harism

New Member
Joined
May 9, 2008
Messages
25
Gender
Male
HSC
2009
Would've been much simpler if you just do:



Question:

Suppose f(x) = 1/x + sin²(πx) / πx². By considering the first derivative, prove that f(x) is decreasing for x > 0.
trebla, put us out of our misery.
is it a pi or an n?

thanks.
 

Drongoski

Well-Known Member
Joined
Feb 22, 2009
Messages
4,255
Gender
Male
HSC
N/A
trebla, put us out of our misery.
is it a pi or an n?

thanks.
Don't think it's pi; trebla is not in the habit of making such a typo.
Provided n > 0 it's all ok. So azureus88's solution stands.
 
Last edited:

harism

New Member
Joined
May 9, 2008
Messages
25
Gender
Male
HSC
2009
Don't think it's pi; trebla is not in the habit of making such a typo.
Provided n > 0 it's all ok. So azureus88's solution stands.
its not a typo, drongoski.
check it yourself... copy what looks like an 'n' and paste it into word. you will see its a pi, not an n.

i had mistaken it for an 'n' myself. But it was gurmies who knocked some sense into me.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top