HSC 2012 MX2 Marathon (archive) (2 Viewers)

math man

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Re: 2012 HSC MX2 Marathon

you're not the only one, it does that for all, however, how do robots gain weight by means of human food?
I thought eating metal would make you gain weight
 

SpiralFlex

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Re: 2012 HSC MX2 Marathon

I eat nuts and bolts and humans.

I better go study or clown will eat me, I will revisit the conics question I posted up, I think it's incorrect.

Post more questions, when I get back tomorrow I shall be having fun on BOS...
 

math man

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Re: 2012 HSC MX2 Marathon

I eat nuts and bolts and humans.

I better go study or clown will eat me, I will revisit the conics question I posted up, I think it's incorrect.

Post more questions, when I get back tomorrow I shall be having fun on BOS...
your conics question is not entirely wrong, the m<0 condition restricts point of contact to quad1 only, so if you lift that conditon the question is fine
 

IamBread

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Re: 2012 HSC MX2 Marathon

I don't want to spoil the party but...

Any chance we could have questions more orientated towards a regular MX2 student, or a little harder, but something that most should at least be able to attempt. A lot of people would probably be scared off, especially since you guys are into or out of uni maths already!
Yeah that's probably a good idea. This one is for people who are doing their HSC, and not done it already,

 

zeebobDD

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Re: 2012 HSC MX2 Marathon

is it bad that i consume maccas atleast 3-4times a week, ontop of other junk food everyday?:S
 

lolcakes52

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Re: 2012 HSC MX2 Marathon

Okay, because im feeling like an idiot and getting it consistently wrong apparently.
 

lolcakes52

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Re: 2012 HSC MX2 Marathon

Okay, I cant use latex so I have to explain it. Basically I let the primitive functions of f(x) and f(a-x) be F(x) and F(a-x) respectively. Then I evaluate them as one would usually and I get F(a)-F(0) and F(0)-F(a).
 

IamBread

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Re: 2012 HSC MX2 Marathon

Well the way I would do it is the way kingkong123 did, except show LHS = RHS, not RHS = LHS.
 

lolcakes52

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Re: 2012 HSC MX2 Marathon

But what I cant understand is why both of methods seem valid and yet they are mutually exclusive.
 

Sidekickk

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Re: 2012 HSC MX2 Marathon

well RHS gives you something to work with, you wouldn't know what to do if you started from LHS.
 

Rezen

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Re: 2012 HSC MX2 Marathon

lolcakes, the if F(x) is the primitive of f(x) then -F(a-x) is the primitive of f(a-x)
 

largarithmic

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Re: 2012 HSC MX2 Marathon

You can like, do that integration thing just by considering the geometry of it right; like sending x -> a-x is the same as reflecting the graph about the line x = a/2, so the area under the curve between 0 and a is preserved
 

Carrotsticks

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Re: 2012 HSC MX2 Marathon

You can like, do that integration thing just by considering the geometry of it right; like sending x -> a-x is the same as reflecting the graph about the line x = a/2, so the area under the curve between 0 and a is preserved
You really like your geometry.

Analysis ftw.
 

IamBread

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Re: 2012 HSC MX2 Marathon

Never thought of it as geometry, I'm not really a geometry person :p
 

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