Inequalities (1 Viewer)

cutemouse

Account Closed
Joined
Apr 23, 2007
Messages
2,250
Gender
Undisclosed
HSC
N/A
Hey guys,

Just wondering, when you solve inequalities (eg. x2-4>0) do you prefer to use the case method, or to draw a facilitating graph and read off it?

What's the better method? I was taught the graphing method, so I'm wondering how you do the case method.

Thanks
 

dp624

Active Member
Joined
Oct 16, 2008
Messages
2,326
Gender
Male
HSC
2008
I like to draw a very rough graph with only the x-axis, the x-intercepts and the general shape.
From there you can infer the answer. But i'm sure you know that
 

PC

Member
Joined
Aug 19, 2004
Messages
639
Location
Sydney
Gender
Undisclosed
HSC
N/A
For something like x2–4>0, a graph is probably sufficient.

For inequations like 1/(x2–4)>0 or 1/|x2–4|>0, definitely by cases.
 

cutemouse

Account Closed
Joined
Apr 23, 2007
Messages
2,250
Gender
Undisclosed
HSC
N/A
PC said:
1/(x2–4)>0
Why would I use cases for that?

Couldn't I just multiply both sides by (x2–4)2 and then use a facilitating graph to read off it?

Oh, and with the 'case method' I was referring to the method that uses no graphs at all.
 

addikaye03

The A-Team
Joined
Nov 16, 2006
Messages
1,267
Location
Albury-Wodonga, NSW
Gender
Male
HSC
2008
jm01 said:
Why would I use cases for that?

Couldn't I just multiply both sides by (x2–4)2 and then use a facilitating graph to read off it?

Oh, and with the 'case method' I was referring to the method that uses no graphs at all.
1/(x^2-4)>0
x^2-4<0
(x-2)(x+2)=0
therefore x=+-2
Then use cases.... i cbf, but basically x-axis, label each area A,B,C.. Test point e.g B (usually x=0, if possible) then rewrite equality.
 

gurmies

Drover
Joined
Mar 20, 2008
Messages
1,209
Location
North Bondi
Gender
Male
HSC
2009
I use a different method, which I use for every inequality there is:

x^2 - 4 > 0

I solve as x^2 - 4 = 0

x = +- 2

Plot those two on a number line, then test outside and between for the inequality. Works for every type of inequality.
 

jet

Banned
Joined
Jan 4, 2007
Messages
3,148
Gender
Male
HSC
2009
for something like x^2-4>0
I would just solve x^2 -4 =0 then test between the two intercepts, namely -2 and 2. I would test x=0.
If it works then its in the interval. If not, then its outside.

Otherwise I'd draw a graph.
 

bored of sc

Active Member
Joined
Nov 10, 2007
Messages
2,314
Gender
Male
HSC
2009
gurmies said:
I use a different method, which I use for every inequality there is:
x^2 - 4 > 0
I solve as x^2 - 4 = 0
x = +- 2
Plot those two on a number line, then test outside and between for the inequality. Works for every type of inequality.
Same method we learnt.
 

cutemouse

Account Closed
Joined
Apr 23, 2007
Messages
2,250
Gender
Undisclosed
HSC
N/A
Hmm, that's a bit different to the method that we learnt... Oh well I think my method's better.. Less mucking around.
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,220
Gender
Male
HSC
2006
I usually use the graph method because it's quicker without the need to consider cases. The only time I would consider testing different cases is if there is a sum/difference of two or more absolute values in the inequality.
 

cutemouse

Account Closed
Joined
Apr 23, 2007
Messages
2,250
Gender
Undisclosed
HSC
N/A
Yeah I use the case method aswell for multiple absolute values in an inequality. But I was wondering what was so good about the case method for doing this, as I've always used the graphing method. Looks like I'll stick with it.
 

Aerath

Retired
Joined
May 10, 2007
Messages
10,169
Gender
Undisclosed
HSC
N/A
Trebla said:
I usually use the graph method because it's quicker without the need to consider cases. The only time I would consider testing different cases is if there is a sum/difference of two or more absolute values in the inequality.
Yeah, that's the way I was taught it, too.
 

kurt.physics

Member
Joined
Jun 16, 2007
Messages
840
Gender
Undisclosed
HSC
N/A
Graphing is probably quicker if its a quadratic, or even a cubic (required that the roots are easily found). Where as if it is hyperbolic or something weird, then multiplying by the square of the denominator, looking at the chases, or even equating the inequality will seem more appropriate.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top