Probability (1 Viewer)

[mr EaZy]

How do u get on with 3 unit adv probability?
I get stuck just looking at the example in fitzpatrick, so i left it at that

any help.? ill come up with a question or someting later...

 

[withoutaface]

How do u get on with 3 unit adv probability?
I get stuck just looking at the example in fitzpatrick, so i left it at that

any help.? ill come up with a question or someting later...

Most of it was pretty easy.

 

[mr EaZy]

i spent today going over 3 unit permutations/combiinations/ im about to move forward to 3unit adv probs. so hang on. im not doin well in 4u,
for the trials i came 2nd last in catholic p and last in the independant. (at 54% and 61%) im not big on math

 

[mr EaZy]

in the meantime try this one. 8 students in a line (queue). 4boys 8 girls. wat is the number of arrangements if boy/girl permutaion is alternating bgbgbg.......or gbgbgbg.....

wat i did was: 8 (first position) 4(2nd for either the boy or girl) 3(2nd for boys).....
so 8.4.3.3.2.2.1.1 =1152. Is this the only way to do it or is there a short cut??

 

[BlackJack]

Order matters. Two possibilities:
bgbgbgbg. all 4 boys are chosen, 4! combinations. 4 out of 8 girls are chosen. 8P4.
gbgbgbgb. identical possibilities.

8P4*4!*2 = 8!*2.

I either do not get what you are saying or you are making a mistake.

 

[mr EaZy]

i did the fitzpatrick questions, it wasn't as hard as i thought it to be, couldn't do the cubes question- something about the colours on each sides, and wat about this:
Q(27?) MAMMAL: 6 letters but arrange the letters such that the M(s) and non- M(s) are in alternating order.

Black jack: i don't think thats the answer as without restrictions the answer is 8!. But the restriction is that boys and girls must alternate. i seem to have made a mistake in typing:
i wrote: 8 students in a line (queue). 4boys 8 girls.
should be: 4 girls, 4 boys. to make 8.

 

[Slidey]

It might be amazing to hear it, but I heard you the first time.

 

[mr EaZy]

i have a tendency to double click or triple click when BOS is running really slooooow!

So can u help me or not?

 

[Constip8edSkunk]

alternating boys and girls: theres 4! ways each of placing boys and girls with either girl starting or boy starting (2 options) so 4!*4!*2

MAMMAL...theres 3!/2 = 3 ways of arranging A,A,L, and you can start with either M or or non-M, so 2*3 = 6 arrangements