Revise through the content and make sure you're thorough with all of em.any thoughts?
spam past papers and learn from any questions that you answered incorrectly.
Revise through the content and make sure you're thorough with all of em.any thoughts?
Will doing chapter review from the textbook be beneficialRevise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.
yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good ideaWill doing chapter review from the textbook be beneficial
Anyone?y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
The domain is correct, but the range is not.Anyone?
How would the range be written as?The domain is correct, but the range is not.
(And the 2 and -2 should be written in curly brackets, like {-2}.)
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?How would the range be written as?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?You said the range is all real numbers excluding 2. But this is not correct. Can you see why?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?
So what would the actual range be?
Horizontal line through the point (0, c).How do you graph y = c?
If you can't tell by inspection, better sketch itSo what would the actual range be?
could it be (2,infinity), even though the graph never touches 2?
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.could it be (2,infinity), even though the graph never touches 2?
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so onYeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.
Would it be open brackets around both 2 and infinity?so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yesso if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yes (for y = 2/[(x+2)^{2}] + 2).Would it be open brackets around both 2 and infinity?