VCE Maths questions help (1 Viewer)

jathu123

Active Member
any thoughts?
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.

boredsatan

Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

boredsatan

Member
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.
Will doing chapter review from the textbook be beneficial

jathu123

Active Member
Will doing chapter review from the textbook be beneficial
yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good idea

boredsatan

Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
Anyone?

InteGrand

Well-Known Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)

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boredsatan

Member
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)
How would the range be written as?

InteGrand

Well-Known Member
How would the range be written as?
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?

boredsatan

Member
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

leehuan

Well-Known Member
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

boredsatan

Member
So what would the actual range be?

boredsatan

Member
How do you graph y = c?

InteGrand

Well-Known Member
How do you graph y = c?
Horizontal line through the point (0, c).

(Where the x-axis is the horizontal axis and the y-axis is the vertical axis, as usual.)

boredsatan

Member
could it be (2,infinity), even though the graph never touches 2?

InteGrand

Well-Known Member
could it be (2,infinity), even though the graph never touches 2?
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.

boredsatan

Member
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

boredsatan

Member
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Would it be open brackets around both 2 and infinity?

InteGrand

Well-Known Member
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yes

InteGrand

Well-Known Member
Would it be open brackets around both 2 and infinity?
Yes (for y = 2/[(x+2)2] + 2).