# VCE Maths questions help (1 Viewer)

#### jathu123

##### Active Member
any thoughts?
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.

#### boredsatan

##### Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

#### boredsatan

##### Member
Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.
Will doing chapter review from the textbook be beneficial

#### jathu123

##### Active Member
Will doing chapter review from the textbook be beneficial
yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good idea

#### boredsatan

##### Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
Anyone?

#### InteGrand

##### Well-Known Member
y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)

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#### boredsatan

##### Member
The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)
How would the range be written as?

#### InteGrand

##### Well-Known Member
How would the range be written as?
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?

#### boredsatan

##### Member
You said the range is all real numbers excluding 2. But this is not correct. Can you see why?
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

#### leehuan

##### Well-Known Member
I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?
$\bg_white \text{Look carefully. It's }\frac{2}{(x+2)^\textbf{2}}+2\\ \text{You've stated the range of }\frac{2}{x+2}+2\text{ without the power of 2. This is not a hyperbola.}$

#### boredsatan

##### Member
$\bg_white \text{Look carefully. It's }\frac{2}{(x+2)^\textbf{2}}+2\\ \text{You've stated the range of }\frac{2}{x+2}+2\text{ without the power of 2. This is not a hyperbola.}$
So what would the actual range be?

#### boredsatan

##### Member
How do you graph y = c?

#### InteGrand

##### Well-Known Member
How do you graph y = c?
Horizontal line through the point (0, c).

(Where the x-axis is the horizontal axis and the y-axis is the vertical axis, as usual.)

#### boredsatan

##### Member
could it be (2,infinity), even though the graph never touches 2?

#### InteGrand

##### Well-Known Member
could it be (2,infinity), even though the graph never touches 2?
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.

#### boredsatan

##### Member
Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

#### boredsatan

##### Member
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Would it be open brackets around both 2 and infinity?

#### InteGrand

##### Well-Known Member
so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on
Yes

#### InteGrand

##### Well-Known Member
Would it be open brackets around both 2 and infinity?
Yes (for y = 2/[(x+2)2] + 2).