VCE Maths questions help (1 Viewer)

[jathu123]

any thoughts?

Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.

 

[boredsatan]

y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

 

[boredsatan]

Revise through the content and make sure you're thorough with all of em.
spam past papers and learn from any questions that you answered incorrectly.

Will doing chapter review from the textbook be beneficial

 

[jathu123]

Will doing chapter review from the textbook be beneficial

yeah I guess, but I'd prefer past papers as it more closely resembles the actual exam. Doing them in exam conditions would be a good idea

 

[boredsatan]

y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

Anyone?

 

[InteGrand]

y = 2/(x+2)^2 + 2
Domain = R\(-2)
Range = R\(2)
Are these right

Anyone?

The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)

 

[boredsatan]

The domain is correct, but the range is not.

(And the 2 and -2 should be written in curly brackets, like {-2}.)

How would the range be written as?

 

[InteGrand]

How would the range be written as?

You said the range is all real numbers excluding 2. But this is not correct. Can you see why?

 

[boredsatan]

You said the range is all real numbers excluding 2. But this is not correct. Can you see why?

I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

 

[leehuan]

I'm a bit confused, because if the domain works like that, then shouldn't the range work like that as well?

 

[boredsatan]

So what would the actual range be?

 

[boredsatan]

How do you graph y = c?

 

[InteGrand]

How do you graph y = c?

Horizontal line through the point (0, c).

(Where the x-axis is the horizontal axis and the y-axis is the vertical axis, as usual.)

 

[leehuan]

So what would the actual range be?

If you can't tell by inspection, better sketch it

 

[boredsatan]

If you can't tell by inspection, better sketch it

could it be (2,infinity), even though the graph never touches 2?

 

[InteGrand]

could it be (2,infinity), even though the graph never touches 2?

Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.

 

[boredsatan]

Yeah that's the range. And it's because the graph doesn't touch 2 that we put an open bracket around the 2.

so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

 

[boredsatan]

so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

Would it be open brackets around both 2 and infinity?

 

[InteGrand]

so if the graph was y = 2/(x+2)^2 + 3, the range would be (3,infinity) and so on

Yes

 

[InteGrand]

Would it be open brackets around both 2 and infinity?

Yes (for y = 2/[(x+2)²] + 2).