+1.infinity isn't a number. Logically, infinity * 0 is 0 but you can never finish multiplying it so it's undefined.
no its 69 hurrr derrrrIs infinity x 0 = -1?
You are right. The gradient of the y axis in undefined.I thought the gradient of y was undefined, not infinity.
y*x = -1
y*0 = -1
y = -1/0
Therefore y is undefined.
Might be completely wrong here though.
It approaches it but never reaches it.And, 0.9 (recurring)=1
I know. But when trying to put into a fraction...how gay lolIt approaches it but never reaches it.
That method thing implies infinity is a constant.I know. But when trying to put into a fraction...how gay lol
It does? Cool. Now maths is pretty stuffed.That method thing implies infinity is a constant.
It does and you can prove it but i cbf right now.It approaches it but never reaches it.
This is the proof.is this a legit proof?...
0.999.... let equal x
10x = 9.999...
10x - x = 9x = 9.999... - 0.999... = 9
ie. 9x=9
x=1
0.999... = 1
is it flawed? or do expert mathematicians reckon this definitely proves 0.999... = 1This is the proof.
they are defined to be perpendicular. the x axis and the y axis arent magical lines that are by nature perpendicularOMG. I know where you guys are comming from. I know the facts.
But I found it interesting. Jeez.
Fine heres a question. Prove that the x axis is perpendicular to the y axis.
(No, i'm not saying infinity x 0 is -1!!!)
No, 0.9 (recurring)=1. Not approaches.It approaches it but never reaches it.