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Australian Maths Competition 2012 Thoughts (1 Viewer)

Sy123

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Does anyone think I can scrape a D with my outcome?
 

4025808

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i think he would know how he went better than you lol :p

have some faith in your brother
LOL well he would do better than me, but from what he did I already pointed out some of the stuff he did wrong, which was at least 40 marks in total (including his own skipping of Qs)

i just don't want him to get too cocky, that's all :L

although id be surprised if he ended up getting 100, maybe even 90 as well

Haha, doesn't he go to my school? I am sure he would've done fine for AMC, though it seems like 100 is pushing it. Unless of course he's a mathematical prodigy which I am told by you, he isn't.
you go to sydney grammar??. he's not a mathematical prodigy. he's musically talented though
 

RivalryofTroll

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lol I think I guessed 1/256

I wished they defined what a GP was, it shouldn't make much difference to the actual level of ability needed in the process to solve the question

oh well, I'm hoping for a distinction anyway
I knew what a GP was but didn't get/understand the question anyways. So guessed it. Like I did for most of the test.
 

Demento1

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you go to sydney grammar??. he's not a mathematical prodigy. he's musically talented though
I think I talked to you at the study meat for a while. Mhm, you mentioned he was a music scholar.
 

bleakarcher

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I knew what a GP was but didn't get/understand the question anyways. So guessed it. Like I did for most of the test.
lol, all you had to do was apply the pythagorean theorem

Let the sides be 2, 2a, 2a^2
(2a^2)^2=(2a)^2+2^2
4a^4=4a^2+4
a^4-a^2-1=0
a^2=[1+sqrt(5)]/2
Hence, hypotenuse=2a^2=1+sqrt(5)
 

Demento1

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lol, all you had to do was apply the pythagorean theorem

Let the sides be 2, 2a, 2a^2
(2a^2)^2=(2a)^2+2^2
4a^4=4a^2+4
a^4-a^2-1=0
a^2=[1+sqrt(5)]/2
Hence, hypotenuse=2a^2=1+sqrt(5)
Pretty much what I did. The idea of 'geometric progression' was made to throw off people although it isn't really that wordy.
 

iBibah

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lol, all you had to do was apply the pythagorean theorem

Let the sides be 2, 2a, 2a^2
(2a^2)^2=(2a)^2+2^2
4a^4=4a^2+4
a^4-a^2-1=0
a^2=[1+sqrt(5)]/2
Hence, hypotenuse=2a^2=1+sqrt(5)
That's what I did too. This kind of question comes in schools too.
 

iBibah

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Pretty much what I did. The idea of 'geometric progression' was made to throw off people although it isn't really that wordy.
Not really to throw off, that's just the term it's called when you do SnS. For people who haven't done the topic it looks weird but becomes quite customary after Year 11.
 

bleakarcher

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I personally reckon I didn't do well, didn't have any sense for time either (spent so much time just sitting there thinking it will end any second now lol). Hadn't done it for like 2 years prior however. Hoping for much better next year.
 

sdort

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So what was the answer for the last few?
I got 6 for 29, although apparently it was 2. Any ideas?
 

giftprize

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Do you know where I can find middle primary and upper primary papers? I am keen to see how my brothers went? Thanks very much!
 

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