CSSA MX2 Trial (2 Viewers)

[Johnstan]

Yes... you find T1 and T2 by themselves. Than you divide. The thing you need to recognise is that tan theta = r/h. and u use that fact to simply T1/T2 to get 5:3



Anybody do the sigma question ????

Last part of last question was only limiting sum so is a/(1-r) correct where a =1 and r = 4/9 (i think)???

yeah lol that was the first question i did out of the whole paper... the limiting sum one.. coz i knew i wud forget the formula if i didnt do it on the spot. <3

 

[maths lover]

does anyone remember the last question exactly?

i don't think anyone would remember it since it was a pretty large sum expressions.

 

[kman16]

Was the probability question in the multis 12 or 9?
I thought it was a fairly simple paper but i ran out of time and left out 14 marks of Q16. Also didnt get all the circle geo out and coordinates of C. I probably got around 65-70%

 

[manscux]

Was the probability question in the multis 12 or 9?
I thought it was a fairly simple paper but i ran out of time and left out 14 marks of Q16. Also didnt get all the circle geo out and coordinates of C. I probably got around 65-70%

Hi while i "educatedly guessed" this question i got 21. Since would you not use 7C5

Also what did people get for that question that said what is the answer to sum of roots cubed --> a^3 + b^3 + c^3 .. it was multi choice and i wrote -125 ?

correct or not

Two of my concerns in multi choice

Anyone do the recurrence formula question in 16 ?

If you read the back of the paper it was written by a some teachers and a guy from UNSW....... we all know which question this UNSW guy wrote

 

[Johnstan]

Hi while i "educatedly guessed" this question i got 21. Since would you not use 7C5

Also what did people get for that question that said what is the answer to sum of roots cubed --> a^3 + b^3 + c^3 .. it was multi choice and i wrote -125 ?

correct or not

Two of my concerns in multi choice

Anyone do the recurrence formula question in 16 ?

If you read the back of the paper it was written by a some teachers and a guy from UNSW....... we all know which question this UNSW guy wrote

haha yes i saw the unsw and im like oh crap.
this is going down....
what did everyone get for the mechanics question?
it was the one with both forces negative ( grav and reisstance) but wat was on top? dv? or vdv?

 

[manscux]

haha yes i saw the unsw and im like oh crap.
this is going down....
what did everyone get for the mechanics question?
it was the one with both forces negative ( grav and reisstance) but wat was on top? dv? or vdv?

vdv with (-g-kv/2) at bottom

 

[Johnstan]

vdv with (-g-kv/2) at bottom

yerps

 

[RealiseNothing]

I can't remember exactly what it was cos I had absolutely no idea where to start. It involved integration with limiting sums or something.

!!!!!!!!!!!!!!!

I wish my school did this paper, these questions are like my strengths lol.

 

[Sindivyn]

Hi while i "educatedly guessed" this question i got 21. Since would you not use 7C5

Also what did people get for that question that said what is the answer to sum of roots cubed --> a^3 + b^3 + c^3 .. it was multi choice and i wrote -125 ?

correct or not

Two of my concerns in multi choice

Anyone do the recurrence formula question in 16 ?

If you read the back of the paper it was written by a some teachers and a guy from UNSW....... we all know which question this UNSW guy wrote

Polynomial MC was 9 (I think). And combinations, Idk, I got 21 and it seemed too simple, so I put 12 instead .

 

[boredj]

holy shiet it was so hard. question 8 killed me

 

[kman16]

And combinations, Idk, I got 21 and it seemed too simple, so I put 12 instead .

LOL thats what i did too

 

[manscux]

For 16 did people express c as log(root A/B) and k as A root A/B

and what did people get for the cylindrical shells question i got pie/2 ?

Also... what how did people prove that the roots of the expression were equal to 5/4 i.e. cos^2 (pie/10) + cos ^2 (pie/5)

 

[Johnstan]

For 16 did people express c as log(root A/B) and k as A root A/B

and what did people get for the cylindrical shells question i got pie/2 ?

Also... what how did people prove that the roots of the expression were equal to 5/4 i.e. cos^2 (pie/10) + cos ^2 (pie/5)

i let them equal alpha beeta ghamma and then did em... got 20/16 so 5/4

 

[abcdefghij123]

does anyone remember the last question exactly?

from memory:
16b)
i) 1 mark algebraic proof --> super easy
ii) recurrence formula for 3 marks using (i) identity... something like prove I(2n+1) = (2n/(2n+1)) x I(2n-1)
iii) prove I(2n+1) = (2^n * n!)/(1x3x5x...x(2n-1)) (2/3marks, can't remember)
iv) i couldn't even get close to typing this one out. it basically was a proof using a summation of iii) for a number of different values of n to get sigma (1/(2n+1)^2) (2marks)
v) using arcsin = x + uglything, prove 1 + 1/3^2 + 1/5^2 ... = pi^2 / 8 (2marks)
vi) find 1 + 1/2^2 + 1/3^2 + ... (2marks

 

[OMGITzJustin]

test was freaking hard, but my teacher cut out the last 3 questions and put his own (told us this before the exam) - which were apparently tailored for our progress in the course. Hardest conics i've ever seen in my life

 

[seanieg89]

from memory:
16b)
i) 1 mark algebraic proof --> super easy
ii) recurrence formula for 3 marks using (i) identity... something like prove I(2n+1) = (2n/(2n+1)) x I(2n-1)
iii) prove I(2n+1) = (2^n * n!)/(1x3x5x...x(2n-1)) (2/3marks, can't remember)
iv) i couldn't even get close to typing this one out. it basically was a proof using a summation of iii) for a number of different values of n to get sigma (1/(2n+1)^2) (2marks)
v) using arcsin = x + uglything, prove 1 + 1/3^2 + 1/5^2 ... = pi^2 / 8 (2marks)
vi) find 1 + 1/2^2 + 1/3^2 + ... (2marks

Ah okay I get you. It sounds like one of the pretty standard ways of evaluating that sum, it must have come up in past papers before.

 

[RealiseNothing]

from memory:
16b)
i) 1 mark algebraic proof --> super easy
ii) recurrence formula for 3 marks using (i) identity... something like prove I(2n+1) = (2n/(2n+1)) x I(2n-1)
iii) prove I(2n+1) = (2^n * n!)/(1x3x5x...x(2n-1)) (2/3marks, can't remember)
iv) i couldn't even get close to typing this one out. it basically was a proof using a summation of iii) for a number of different values of n to get sigma (1/(2n+1)^2) (2marks)
v) using arcsin = x + uglything, prove 1 + 1/3^2 + 1/5^2 ... = pi^2 / 8 (2marks)
vi) find 1 + 1/2^2 + 1/3^2 + ... (2marks

Basel Problem!

 

[bleakarcher]

=(

Wanna see the paper.

 

[seanieg89]

The final question would be walking you through proof #3 in http://empslocal.ex.ac.uk/people/staff/rjchapma/etc/zeta2.pdf I presume.

 

[bleakarcher]

Why is Basel Problem so common in MX2 exams?

They've used the living shit out of it.