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Maths is great. It's the only subject in which the material to study is clear cut and logical. There is no fluff. It's a case of question, method(s), solution(s). Also, if you are burnt out it I assure you it is the subject you'll be able to bounce back into study mode with.

I wish I could sacrifice procrastination.

Just remember, it's not really ideas that are cliche, it's the language that makes the ideas seem cliche.

Theme = melody.

My sister does Radiology. She gained a UAI of 88.05 (from memory). If that's any indication.

Haha.

Not telling people about this site since it has such good resources.

Process driven: belonging is dynamic, ongoing and changing. One journeys towards the state of belonging. Alienation: when one does not belong to an entity i.e. feelings of isolation, loneliness and social awkwardness. Similarity: the features in common with the members of a group...

Multiculturalism I think.

As Kaz said, two point formula (see his top line of working for the formula).

Look up the film clip on you tube (for the linkin park song). It is good to use as a related text in itself.

Friday's music period - it's always performance.

Identify (with examples) three sound techniques, three language techniques and three image techniques (create imagery) as used in poetry.

3+4i = (a+ib)2 = a2+2iab-b2 now we equate real and imaginary parts: therefore 3 = a2-b2 --- (1) 4 = 2ab --- (2) from (2) b = 2/a (3) sub into (1) 3 = a2-(2/a)2 3 = a2 - 4/a2 3a2 = a4-4 a4-3a2-4 = 0 (a2-4)(a2+1) = 0 but a is real so only take a2-4 thus a = +2 sub...

r = rt(32+42) = rt(9+16) = rt25 = 5 theta = tan-1(4/3) = 53.13010235o = 53o (to nearest degree) so 3+4i = 5cis53 in mod-arg form

For 1+rt3i r = rt[12+(rt3)2] = rt(1+3) = rt4 = 2 tan(alpha) = rt3/1 alpha = tan-1(rt3/1) = 60o therefore 1+rt3i = 2cis60 (1+rt3i)z = (2cis60)(cistheta) = 2cis(theta+60) ---- (2) ---- laws of multiply complex numbers i.e. multiply moduli and add arguments thus, alpha = 60o...

By induction: i) Show for n = 1. (-1+rt3i)1-(-1-rt3i)1 = -1+rt3i+1+rt3i = 2rt3i = purely imaginary i.e. real part = 0 ii) Assume true for n=k (-1+rt3i)k-(-1-rt3i)k = Mi where M is the coefficient of the complex number iii) Prove true for n=k+1 (-1+rt3i)k+1-(-1-rt3i)k+1 =...

Here's my assignment on Byron Bay. Pages 6 and 7 have what you are looking for.

Here's one of mine. It's not 20/20 but it's okay. Actually, I wrote a shorter version of this in my year 10 trial and gained 19/20 so I guess it's okay.

Re: Supplementary Texts Oh really? I think I'll have 2. Maybe 3.