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could sum1 please do the following? 1) a particle is projected 30ms at the foot of an inclined plane which is 30∘ to the horizontal. For what angles of projection will the particle strike the incline plane a) horizontally b) perpendicularly 2) a vertical pole subtends an angleα at a point P...

the last senr questions seems impossible. sum phys olympiad guy sed u use a rotating frame of reference?

my school sydney boys still have volumes, conics, mechanics, harder 3u we are quite slow

how do u do the following

i can barely understand what your asking in q.3 but if u let x1 = x2 =...=xn = x then LHS = sin(nx) = RHS = a1sinx + a2sinx +...+ansinx = (a1 + a2 +a3... + an)sinx however that is only smaller than nsinx if a1,a2 etc is smaller than 1 ----- and for your q2 i again dont...

for q1. its not asking to find cos5x in terms of sinx its asking for solutions of x use the general formula i.e sinx = cos5x -------------------1 5x = 2nπ ± cos (sinx) --------------------2 = 2nπ ± ( 1 - x ) and simplify

thankyou so theres no case when you use the negative squareroot right?

but going from root(cos^2 θ) to cosθ is what troubles me for example since you are saying root(cos^2 θ) = cosθ if you let θ = 180 then RHS = 1 LHS = -1 thats what bugs me which i still cant explain.

hi, my thinking has got me a little confused. say you need to integrate root(4 - x^2) then i let x = 2sinθ , dx = 2cosθ dθ but when i simplify 2 x root(1 - sin^2 θ) , how do i know whether to put cosθ or -cosθ ??? i cant figure out the domain restrictions or whatever you need to...

no note really. especially when ur just given the sketch of a function f(x) and not told the actual function. if you are given a function, dont draw inflexions initially but you should check if you have time

u say 6m from the centre. this could be +6 or -6 so cldnt ur amplitude be -6?

i go Sydney Boys High School. fuck we're the onli class doing wilds swans, soo unlucki. i heard something lyk less than 10 schools in NSW do wild swans. :'( share NOTES! especially all you seftonersssss

hi still not quite 100% on this one.. altho ur second method was good thanks how is dividing each term , different to dividing both sides? if u have x^2 - x = 0 then you go x(x-1) = 0 so x = 0,1 hows this different from --------------------2 2sinxcosx - 3sin x = 0 then...

yeh i mean from the eqn --------------------2 2sinxcosx - 3sin x = 0 -----------------------------------------2 how can u just divide that by cos x shouldnt u factorise it out so that --------------------2--------2--------2 2sinxcosx - 3sin x = cos x( 3 tan x - 2 tan x) = 0 and that wld...

as long as you explained it properly.. maybe lyk say (converse of angles subtended by equal chords/arcs)

Hi just one query To solve sin2x + cos2x = (sinx)^2 + 1 the book teaches to expand to -------------------2--------2---------2---------2----------2 2sinxcosx + cos x - sin x = sin x + sin x + cos x --------------------2 2sinxcosx - 3sin x = 0 ---------------------------2 then DIVIDING by...

cld some1 do this one: two satellites have altitudes of 400 and 4000km respectively. Take R to be the avg radius of orbit and T as the period for one orbit. The ratio (R^3/T^3) of the first satellite compared to the second one is...? all i can gather is r^3/t^2 is constant. ---- also...

hey soz added 2 new q's

richard n aaron. such rivals yet such friends

yeh saw it. some of the skits are taken form the british one and some are re-done .. usually quite badly e.g. the "im swiss" one