HSC 2012 MX1 Marathon #1 (archive) (2 Viewers)

[IamBread]

Re: 2012 HSC MX1 Marathon

Part of human condition is to make mistakes. You often see people at the top of their professions make the most ridiculous mistakes.

- Care needs to be taken young grasshopper. I once tried to convince a teacher 1/3 is greater than a half. I was obviously on sugar.

*GROWL*

Haha oh spiral you genius! I've probably done things just as bad. You be surprised how many stupid mistakes people make.

 

[SpiralFlex]

Re: 2012 HSC MX1 Marathon

Haha oh spiral you genius! I've probably done things just as bad. You be surprised how many stupid mistakes people make.

To my defence, I was on this.

 

[Carrotsticks]

Re: 2012 HSC MX1 Marathon

I will now ridicule a BOS member.

"By doing nothing, you are doing something". - A vegetable and a stick.

...

 

[math man]

Re: 2012 HSC MX1 Marathon

those cookies make you say the darnest things

 

[SpiralFlex]

Re: 2012 HSC MX1 Marathon

Huh?

 

[math man]

Re: 2012 HSC MX1 Marathon

you ridiculing carrotsticks

 

[SpiralFlex]

Re: 2012 HSC MX1 Marathon

I am sorry.

 

[math man]

Re: 2012 HSC MX1 Marathon

it's alright, just lay off those cookies till after hsc

 

[SpiralFlex]

Re: 2012 HSC MX1 Marathon

Never!

 

[math man]

Re: 2012 HSC MX1 Marathon

well then suffer all the silly mistakes, (1/3 > 1/2)

 

[Carrotsticks]

Re: 2012 HSC MX1 Marathon

well then suffer all the silly mistakes, (1/3 > 1/2)

But 1/3 > 1/2 since 3 > 2.

Q.E.D



derp.

 

[math man]

Re: 2012 HSC MX1 Marathon

Well of course, you ended your
Proof with qed and open square,
Must be a solid proof

 

[Timske]

Re: 2012 HSC MX1 Marathon

can someone check my answers
is 3xe^2x d/dx = 6e^2x?
and d/dx e^(x^2-9x) + 2x^2 = (2x - 9)e^(x^2-9x) + 4x

and also the volume of the curve y=e^x rotated about the x axis from x=0 and x = 2.

v=pi int{0}-{2} e^2x = pi [ 2e^2] = pi ( 2e^4 - 2e^0) = (2e^4 - 2)pi cubic units

 

[SpiralFlex]

Re: 2012 HSC MX1 Marathon

Your first one is incorrect. There's a variable x in front of the exponential.

The last one, you integrated it incorrectly. Put 0.5 at the front of the integral.

 

[Timske]

Re: 2012 HSC MX1 Marathon

can u show

 

[AAEldar]

Re: 2012 HSC MX1 Marathon



Have to use the product rule.

 

[Timske]

Re: 2012 HSC MX1 Marathon

omg totaly forgot///

 

[barbernator]

Re: 2012 HSC MX1 Marathon

definite integral from -1 to 1 of 1/x

 

[Timske]

Re: 2012 HSC MX1 Marathon

 

[bleakarcher]

Re: 2012 HSC MX1 Marathon

definite integral from -1 to 1 of 1/x

0.