the base of the triangle is the far right x coordinate where it ends (x=1) minus the coordinate of R which is where it starts. In part i) you proved that R has an x coordinate of r-1/r which is why it's thatHow did you get the base of the triangle to be 1- r-1/r
Anytime my friend!Gosh Daym jimmy, I can always count on you
Do you need help or have a question about this?Hivaclibtibcharkwa said:
No worries, yeah that's pretty much it!The end result is e^-x which then goes down to the denominator
COT is positive in the 3rd quadrantHivaclibtibcharkwa said:
"How do you answer?" You select a letter from the MC lmao.Hivaclibtibcharkwa said:
Worked solutions, he posted the same question previously if I'm not wrong.is that your working or the worked solutions working?
Lmao happy to help hahaha.Thank you genius, I’m saying how do you solve for this question. How does a data set without outliers lead to this answer
Are you sure? A horizontal line gives a gradient of 0. You are asked to find f(6), which is relevant to the original function. Isn't this the reason you are required to integrate? Isn't the gradient determined using the original function, as seen in the graph of y = f(x) I posted?If you look on the image I posted. I think it has something to do with the line being on y=-3.
Since in the derivative if you sub in x, the y value would the gradient.
But we’ll have to wait for the math people to reply to this
The m = -3 comes from graph the being f'(x).